(一)恒等式及因式分解1.a2-b2=(a+b)(a-b)2.a3-b3=(a-b)(a2+ab+b2)3.a3+b3(a+b)(a2-ab+b2)4.(a+b)2=a2+2ab+b25.(a-b)2=a2-2ab+b26.(a+b)3=a3+3a2b+3ab2+b37.(a-b)3=a3-3a2b+3ab2-b38.(a+b+c)2=a2+b2+c2+2(ab+bc+ca)9.(a+b+c)3=a3+b3+c3+3(b2c+bc2+c2a+ca2+a2b+ab2)+6abc10.an-bn=(a-b)( (共 1481 字) [閱讀本文] >>